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Created: Jul 17, 2019
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Inferential Statistics Report
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I. Introduction

a.    Group 3 designed a survey that looked into healthy habits of our friends and family. We wanted to know if they had health insurance, did they go to the Doctor often, eat fast food frequently and sit together as a family. We chose to poll our family and friends via Facebook and face to face questioning, so it wasn’t a random sample. Everyone was able to respond voluntarily therefore it was a sample of convenience. 

b.    Below were our questions:
-Do you have health insurance? 
  yes 
  no 

-How many times a year do you go to the Doctor? 
 Enter a numeric response.

-In a typical week, how many times do you get fast food? 
 Enter a numeric response.
-In a typical week, how often do you sit together as a family? 
 never 
 sometimes 

 often II.Looking at a Categorical-Variable 

a.    Do you have health insurance (yes or no)?    

 

Result 1: Pie Chart With Data Insurance   [Info]
Right click to copy

From the pie chart we were able to determine that of the 163 people we questioned 92.02% of the population had health insurance and only 7.98% did not. 

 

 

b.    Result 2: One sample Proportion with summary 95% Confidence interval results. 

Result 2: One sample proportion confidence interval   [Info]

One sample proportion confidence interval:


Outcomes in : Insurance
Success : yes
p : Proportion of successes
Method: Standard-Wald

95% confidence interval results:
VariableCountTotalSample Prop.Std. Err.L. LimitU. Limit
Insurance1501630.92024540.0212195370.878655870.96183493


Interpretation of the confidence interval:

Shown above are the results of a 95% confidence interval for the population that answered yes to our question “Do you have health insurance”. What this tells us is that if we chose different samples 95% of them would result in confidence intervals that contain the true proportion. Given the data we can be 95% confident that our sample proportion contains the true proportion and that 95% of our population that would answer yes to this question is between 0.878 to 0.961.

 

 

III. Looking at a Numerical Variable

The responses to the question “In a typical week, how many times to you get fast food?” is shown in the histogram and summary stats below. 

 

Result 3: Histogram inferential statistics   [Info]
Right click to copy

Result 4: Summary Stats   [Info]

Summary statistics:


ColumnnMeanVarianceStd. dev.Std. err.MedianRangeMinMaxQ1Q3
fast food1622.17283957.92025152.81429410.2211118311201203

 

b.    A 95% confidence interval for the population mean is shown below. 

Result 5: One sample T confidence interval mean   [Info]

One sample T confidence interval:


μ : Mean of variable

95% confidence interval results:
VariableSample MeanStd. Err.DFL. LimitU. Limit
fast food2.17283950.221111831611.73618612.6094929

We are 95% confident that within our population, the average number of times people eat fast food per week is between 1.7 to 2.6 times per week. 

Because the sample size is more than 30 and the population standard deviation is unknown, I used the t-distribution.


HTML link:
<A href="https://www.statcrunch.com/5.0/viewreport.php?reportid=88454">Inferential Statistics Report</A>

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