Introduction:
a. My group and I designed a survey to learn about weight loss and desire to get fit either for themselves or as recommended by a HealthCare Provider. The population sampled was of American Adults. The results obtained were convenience sample with voluntary responses using social media (facebook) and printed surveys in office settings. The persons made of the sample were persons know via social media or those worked with in an office setting.
b. Our Survey asked the following questions:
1. What is your persoal goal weight loss that would make you happy?
2. What is your current weight?
3. Has a Health Care Provider recommended to you the need to lose weight to control an actual or potential medical problem? Yes/No?
4. How Motivated are you reach your New Year's Weight loss? Choose one of the following:
(5) Very motivated
(4) Motivated
(3) Somewhat Motivated
(2) Unmotivated
(01) Very Unmotivated
This report was collected using Statcrunch and focuses on New Year's Weight Loss survey regarding weight loss.
II. Looking at a categorical variable
a. THe responsses to the question "Typically, do you feel rested when you wake up?" are shown in the pie chart.
From the pie chart above we can see 19.67% of the 60 respondants had recommended weight loss. 80.33% of the 60 respondants did not recieve recommended weigh loss from their providers.
b. Result 2. One sample Proportion with Summary: 95% confidence interval results:
P: Proportion of success for population
Method: statndardwald
One sample proportion confidence interval:
p : Proportion of successes Method: StandardWald 95% confidence interval results:

Interpretation of the confidence Interval: Above is the 95% confidence Intervalresults for the propotion of theis group that answered yes to the question, " Has a Health Care Provider recommended to you the need to lose weight to control an actual or potential medical problem?." The 95% confidence interval indicates that if you were to select n=60, approximietly 95% of the respondants contains a true proportion. When looking at the above interval we can say that we are 95% confident our confidence interval contains a true propution of our population and would answer yes to the question 0.098 to 0.301.
E= (.301.200)/2=0.0301
III. Looking at a Numerical Variable
a. THe responses to the question "What is your current weight?" are shown in the histogram and the summary statistics.
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b. A 95% confidence interval for the population mean is shown.
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Interpretation of the confidence Interval: A 95% confidence interval means that if selecting n= 60, we would be 95% confident these samples would contain a true proportion mean. The results indicate a sample mean of 175.7 lbs would occur between 167.1 and 184.2 lbs.
I used a Tinterval, the population st. deviation was unknown.
Interpretation of the confidence Interval: A 95% confidence interval means that if selecting n= 60, we would be 95% confident these samples would contain a true proportion mean. The results indicate a sample mean of 175.7 lbs would occur between 167.1 and 184.2 lbs.
I used a Tinterval, the population st. deviation was unknown.
Thank you
Summary statistics:

One sample T confidence interval:
μ : Mean of population 95% confidence interval results:

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