PART ONE
In this project I will study the population of families in the town of Sycamore that have children 5 years and younger in daycare.
The parameter I would like to investigate is the proportion of these families that utilize facilityrun daycare for their children.
The following survey will be distributed to collect data about the above population and suggested parameter:
1. Are you a parent of a child that is 5 years or younder and in daycare?
2. What gender do you identify as? (Male or Female)
3. Does the child attend daycare fulltime?
4. Does your child attend a facilityrun daycare?
5. Do you get any financial assistance to place your child in daycare?
I anticipate that the proportion of children that are 5 years or older attend a facilityrun daycare is larger compared to those that use parent/family members for child care.
PART TWO
I used the convience type sampling since I surveyed some parents from my daughters school at a preschool gathering. This type of sampling can be bias since it does not really represent the population as a whole even though it would be a good representation of this school.
The following is a link to the survey:
http://www.statcrunch.com/5.0/survey.php?surveyid=11888&code=BHBMI
Question One, (Are you a parent of a child that is 5 years or younder and in daycare?), is qualitative data with a nominal level of measurement.
Question Two, (What gender do you identify as?), is qualitative data with a nominal level of measurement.
Question Three, (Does the child attend daycare fulltime?), is qualitative data with a nominal level of measurement.
Question Four, (Does your child attend a facilityrun daycare?), is qualitative data with a nominal level of measurement. This is the main parameter question.
Question Five, (Do you get any financial assistance to place your child in daycare?), is qualitative data with a nominal level of measurement.
The proportion of children that are 5 years or older attend a facilityrun daycare compared to those that use parent/family members for child care was found to be 18 out of 37.
P^= 0.514
Standard deviation= 0.082
The proportion does show that more than 50% of families do use facility run day care but the standard deviation is relatively large compared to the proportion so the true results will have to be determined after the hypothesis tests.
Hypothesis Test
I anticipate that the proportion of children that are 5 years or older attend a facilityrun daycare is greater compared to those that use parent/family members for child care.
The null hypothesis is that proportion of children that are 5 years or older attend a facilityrun daycare compared to those that use parent/family members for child care will be 0.500.
The alternative hypothesis is that proportion of children that are 5 years or older attend a facilityrun daycare compared to those that use parent/family members for child care is greater than 0.500.
I need to do a righttailed test since we are testing whether the population parameter lies to the right of the claimed value.
The sample proportion is 19/37, 0.514, the standard deviation in the sample is 0.082 and the n is 37.
standard deviation calculation:
SQRT((0.5*(10.5)/37)= 0.082
Since we have a sample size over 30 and we are using proportion statistics we are using the normal distribution. We would use the T distribution if we did not have a population of at least 30.
Z value calculation:
Z= 0.5140.5/(SQRT((0.5*(10.5)/37))
Z= 0.171
when using the Z table the z number was rounded to 0.2.
From the Z table we got P=(10.5987)= 0.4013 (We must subtract from one since we are doing a righttailed test)
We should not reject the null hypothesis since our Z value was not greater than 1.645. Also, since the p value is greater than 0.05 we can not say it would be statistically significant.
In conclusion, we can say that my claim, that the proportion of children that are 5 years or older attend a facilityrun daycare is greater compared to those that use parent/family members for child care, was incorrect. The proportion is roughly 50 %.
Frequency table results for var3:
Count = 37

Frequency table results for var4:
Count = 37

Frequency table results for var5:
Count = 37

Frequency table results for var6:
Count = 37

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