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Owner: levkira
Created: Sep 18, 2012
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Inferential Statistical Report
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I. Introduction

I. A. 1. The purpose of my survey is to analyse situation with flooding.

    2. I collected data from my coworkers in the hospital and from my neibours.

    3. People of different ages and occupations who live in New York.

    4. I collect data using personal contacts.

B.  These are my 4 questions:

     1. What is your age?

     2. Do you live in flood zone? ( Choose yes or no)

     3. If you have flood insurance how many years have you had it? a. 2 or less, b. 3-6; c.. 7-10; 

         d. 11-14; e. 15 or more; f. I currently do not have insurance.

     4. How many times have your property in question flooded.



11. Looking at a Categorical Variable

a. Responses to the question "Do you live in the flood zone?" Yes or No are shown below.

b.  95% confidence interval results:
p : proportion of successes for population
Method: Standard-Wald

Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit
p 85 101 0.84158415 0.03633184 0.7703751 0.9127933



Interpretation of the confidence interval: Above is the 95% confidence interval results for the question in the table of the results #4 such as "Do you live in flood zone?" Yes or No. We interpret this by saying that we are 95% confident that the interval from 0.770 to 0.913 actually does contain the true value of the population proportion p. This means that if we were to select many different samples of size n=101, approximately 95% of them will contain the true proportion p.

The error term is E=0.913-0.842=0.071


 From the pie chat above we are able to conclude that 84 out of 100 respondents or 84.16% do not live in the flood zone, 15 respondents live or 14.85% live in the flood zone.

III. Looking at a Numerical Variable


 Above is the  response to the question "What is your age?"

Summary statistics:

Column n Mean Variance Std. Dev. Median Range Min Max Q1 Q3
var5 100 44.31 175.85242 13.260936 46 63 13 76 34 52



b. A 95% confidence interval for the population mean is shown below.

 95% confidence interval results:
μ : mean of Variable

Variable Sample Mean Std. Err. DF L. Limit U. Limit
var5 44.31 1.3260936 99 41.67874 46.941257



I am 95% confident that the interval from 42 to 47 of age actually does contain the true value of the the population mean reporting the age. That means that if we were to select many different samples of size n=100, approxiamately 95a% of them will contain the true population mean, mu.

The t distribution was used because the population standard deviation is unknown.


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